알고리즘
1. 카드뭉치
풀이:
def solution(cards1, cards2, goal):
answer = []
n = len(cards1)
m = len(cards2)
i = j = 0
for word in goal:
if i < n and word == cards1[i]:
answer.append(cards1[i])
i += 1
if j < m and word == cards2[j]:
answer.append(cards2[j])
j += 1
return 'Yes' if answer == goal else 'No'
풀이:
def solution(k, m, score):
answer = 0
score.sort(reverse=True)
num = (len(score)//m)*m
arr = []
for i in range(1, num+1):
arr.append(score[i-1])
if i%m == 0:
answer+=min(arr)*m
arr=[]
return answer
풀이:
def solution(answers):
answer = [0 for i in range(3)]
man1 = [1,2,3,4,5]
man2 = [2,1,2,3,2,4,2,5]
man3 = [3,3,1,1,2,2,4,4,5,5]
for i in range(len(answers)):
ans = answers[i]
if(man1[i%len(man1)] == ans):
answer[0] += 1
if(man2[i%len(man2)] == ans):
answer[1] += 1
if(man3[i%len(man3)] == ans):
answer[2] += 1
result = []
for i in range(len(answer)):
if(answer[i] == max(answer)):
result.append(i+1)
return sorted(result)