double solution(int numbers[], size_t numbers_len) {
double answer = 0;
for (int i = 0; i < numbers_len; i++){
answer += numbers[i];
}
answer /= (numbers_len);
return answer;
}
풀이:
#include <stdio.h>
#include <stdbool.h>
#include <stdlib.h>
char* solution(int num) {
// 리턴할 값은 메모리를 동적 할당해주세요
char* answer = (char*)malloc(sizeof(char));
if(num%2==0){
answer = "Even";
}else{
answer = "Odd";
}
return answer;
}
SELECT animal_id, name
from animal_ins
where intake_condition = 'sick';