문제 6개를 풀어보자!

#include <iostream>
#include <string>
using namespace std;
int main() {
string a = "When in Rome, do as the Romans.";
cout << a.find("Rome");
}

#include <iostream>
#include <string>
using namespace std;
int main() {
string a;
getline(cin, a);
a.erase(a.find("-"), 1);
cout << a;
}

#include <iostream>
#include <string>
using namespace std;
int main() {
string haming1 = "AAAAA21346";
string haming2 = "AAAAA123451231234";
//삼앟ㅇ연산자
int shortest = haming1.length() < haming2.length() ? haming1.length() : haming2.length();
int answer = 0;
for (int i = 0; i < shortest; i++) {
if (haming1[i] == haming2[i]) continue;
else answer++;
}
cout << answer;
}

#include <iostream>
#include <string>
using namespace std;
int main() {
string ming2;
cin >> ming2;
for (int i = 0; i < ming2.length(); i++) {
if (ming2[i] == 'o') ming2[i] = 'x';
}
cout << ming2;
}

#include <iostream>
#include <string>
using namespace std;
int main() {
string a;
getline(cin, a);
int asdf = a.length();
for (int i = 0; i < asdf; i++) {
a.push_back(a[0]);
a.erase(0, 1);
cout << a << endl;
}
}
공백을 포함한 문장 2개를 받아서 공백업ㄹㅅ이 출력하자.

#include <iostream>
#include <string>
using namespace std;
int main() {
string a;
string b;
getline(cin, a);
getline(cin, b);
for (char c : a) {
if (c != ' ') cout << c;
}
for (char c : b) {
if (c != ' ') cout << c;
}
}