수 조작하기 2

풀이

def solution(numLog):
    answer = ""
    for i in range(1, len(numLog)):
        gap = numLog[i] - numLog[i-1]
        if gap == 1:
            answer += 'w'
        elif gap == -1:
            answer += 's'
        elif gap == 10:
            answer += 'd'
        elif gap == -10:
            answer += 'a'
    return answer