CodeKata
SQL
LeetCode: Customer Placing the Largest Number of Orders
with order_cnt as (
select
customer_number
, count(*) as cnt
from
Orders
group by
customer_number
)
select
customer_number
from
order_cnt
where
cnt = (select max(cnt) from order_cnt)
;
참고할 만한 다른 풀이
SELECT CUSTOMER_NUMBER
FROM ORDERS
GROUP BY CUSTOMER_NUMBER
ORDER BY COUNT( CUSTOMER_NUMBER ) DESC LIMIT 1 ;
Python
85. 연속 부분 수열 합의 개수
from collections import deque
def solution(elements):
answer = 0
s = set()
deq = deque(elements)
for i in range(len(deq)):
sum = 0
for e in deq:
sum += e
s.add(sum)
deq.append(deq.popleft())
answer = len(s)
return answer
데이터 파이프라인 구축 강의
6회차
리눅스 명령어
우분투에서 MySQL 사용
최종 프로젝트
인과관계분석인과관계분석
회고