https://school.programmers.co.kr/learn/courses/30/lessons/59042
SELECT o.ANIMAL_ID, o.NAME from ANIMAL_OUTS o where not exists
(select i.ANIMAL_ID from ANIMAL_INS i where i.ANIMAL_ID = o.ANIMAL_ID);
SELECT o.ANIMAL_ID, o.NAME
from ANIMAL_OUTS o
where not exists
(select 1 from ANIMAL_INS i where i.ANIMAL_ID = o.ANIMAL_ID)
order by o.ANIMAL_ID;