[백준] if문 추가문제 문풀

2525번 오븐 시계

import java.util.Scanner;
 
public class Main {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int h = sc.nextInt();
    int m = sc.nextInt();
    int N = sc.nextInt();
    int M=0;
    if(N<60){
      M=m+N;
      if(M<60){
      System.out.println(h+" "+M);}
      else{
        M=M-60;
        h=h+1;
    if(h>=24){
          System.out.println((h-24)+" "+M);
        }
    else        
      System.out.println(h+" "+M);
        }
    }
    else if(N>=60){
      M=m+N;
      int a= M/60;
      int b= M%60;
      h=h+a;
     if(h>=24){
          System.out.println((h-24)+" "+b);
        } 
    else      
       System.out.println(h+" "+b);
    }
    }
	}

• hour가 24를 넘어갈 때 조건 추가 안할 뻔 했다..!

2480번 주사위 세개

import java.util.Scanner;
 
public class Main {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int a = sc.nextInt();
    int b = sc.nextInt();
    int c = sc.nextInt();
    int money=0;
    if(a==b&&b==c)
      money=10000+a*1000;
    else if((a==b&&a!=c))
      money=1000+a*100;
    else if (a==c&&a!=b)
      money=1000+a*100;
    else if(b==c&&b!=a)
      money=1000+b*100;
    else if(a!=b&&b!=c)
    {if(a>b&&a>c)
        money=a*100;
    else if(b>a&&b>c)
        money=b*100;
    else if(c>a&&c>b)
        money=c*100;
      }
    System.out.println(money);
    }
	}

• 쉬웠다!