#2501
N,K = map(int,input().split())
result = []
for i in range(1,N+1):
if N%i == 0:
result.append(i)
if len(result) < K:
print(0)
else:
print(result[K-1])
#3460
T = int(input())
for _ in range(T):
n = int(input())
ans = ''
# 8 4 2 1
# 13이면 1 1 0 1
while n>0:
ans += str(n%2)
n = n//2
for i in range(len(ans)):
if ans[i] == '1':
print(i, end=' ')
#10818
present = 0
station = 0
Max_present = -21e8
for _ in range(10):
down, up = map(int,input().split())
predown_present = present - down
preup_present = present + up
if predown_present<=0 :
present = 0
else:
present -= down
if preup_present >= 10000:
present = 10000
else:
present += up
Max_present = max(present, Max_present)
print(Max_present)
t = int(input())
ans = [0,1]
if t>=2:
for i in range(2,t+1):
ans.append(ans[i-2]+ans[i-1])
print(ans[-1])
else:
print(ans[t])
t = int(input())
if t == 0:
print(0)
elif t == 1:
print(1)
else:
a, b = 0, 1
for _ in range(2, t + 1):
a, b = b, a + b
print(b)
#2309
lst = [int(input()) for _ in range(9)]
flag = True
for i in range(9):
if flag:
for j in range(i+1, 9):
ex_1 = lst[i]
ex_2 = lst[j]
if sum(lst) - ex_1 - ex_2 == 100:
lst.remove(ex_1)
lst.remove(ex_2)
flag = False
break
print(*sorted(lst), sep='\n')
#1978
N = int(input())
arr = list(map(int,input().split()))
ans = 0
for a in arr:
cnt = 0
for i in range(1,a+1):
if a%i == 0:
cnt +=1
if cnt == 2:
ans += 1
print(ans)
1292 - 쉽게 푸는 문제
✔extend와 append의 차이
list1 = [1, 2, 3]
list2 = [4, 5, 6]
list1.extend(list2)
print(list1) # 출력: [1, 2, 3, 4, 5, 6]
list1.append(list2)
print(list1) # 출력: [1, 2, 3, [4, 5, 6]]
#1292
A,B = map(int,input().split())
def gen_arr(n):
arr = []
for i in range(1,n+1):
arr.extend([i]*i)
return arr
def get_sum(arr,st,ed):
return sum(arr[st-1:ed])
a = gen_arr(A+B+1)
b = get_sum(a,A,B)
print(b)
#2581
M = int(input())
N = int(input())
ans = []
for i in range(M,N+1):
cur = 0
for j in range(1,i+1):
if i%j == 0:
cur +=1
if cur == 2:
ans.append(i)
if len(ans) == 0:
print(-1)
else :
print(sum(ans))
print(ans[0])
import math
a,b = map(int,input().split())
print(math.gcd(a,b)) #최대공약수
print(math.lcm(a,b)) #최소공배수