320. 완전제곱수

백준

1. C++

#include <iostream>
#include <math.h>
using namespace std;
int m, n;
int main() {

	cin >> m >> n;
	int s = 0, minimum = INT_MAX;
	for (int i = m; i <= n; i++) {
		if (sqrt(i) - int(sqrt(i)) == 0) {
			s += i;
			if (minimum > i) minimum = i;
		}
	}

	cout << s << endl << minimum;
	return 0;

}