# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def closestValue(self, root: TreeNode, target: float) -> int:
self.ans = float(inf)
def dfs(node, target):
if node is None: return
self.ans = node.val if abs(target-node.val) < abs(target-self.ans) else self.ans
dfs(node.left, target)
dfs(node.right, target)
dfs(root, target)
return self.ans
class Solution:
def closestValue(self, root: TreeNode, target: float) -> int:
q = [root, None]
ans = float(inf)
while q:
node = q.pop(0)
if node is None:
if q: q.append(None)
else:
if abs(target-node.val) < abs(target-ans):
ans = node.val
if node.left:
q.append(node.left)
if node.right:
q.append(node.right)
return ans
https://leetcode.com/problems/closest-binary-search-tree-value/