Leetcode 7. Reverse Integer

Mingyu Jeon·2020년 4월 26일
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class Solution:
    def reverse(self, x: int) -> int:
        ans = 0
        minus = False
        
        if x < 0: minus = True
        if 0 <= x < 10: return x
        
        temp = list(str(abs(x)))[::-1]
        ans = int(''.join(temp))
        if minus: ans *= -1

        return ans if -2**31 < ans < 2**31 else 0     

https://leetcode.com/problems/reverse-integer/

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