Given a sorted array of distinct integers and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.
You must write an algorithm with O(log n) runtime complexity.
Example 1:
Input: nums = [1,3,5,6], target = 5
Output: 2
Example 2:
Input: nums = [1,3,5,6], target = 2
Output: 1
Example 3:
Input: nums = [1,3,5,6], target = 7
Output: 4
Example 4:
Input: nums = [1,3,5,6], target = 0
Output: 0
Example 5:
Input: nums = [1], target = 0
Output: 0
Constraints:
1 <= nums.length <= 104
-104 <= nums[i] <= 104
nums contains distinct values sorted in ascending order.
-104 <= target <= 104
var searchInsert = function(nums, target) {
if (nums.indexOf(target) !== -1) {
return nums.indexOf(target)
}
for ( num of nums ) {
if(num > target) {
return nums.indexOf(num)
}
}
return nums.length
};
Runtime: 72 ms, faster than 81.82% of JavaScript online submissions for Search Insert Position.
Memory Usage: 40 MB, less than 12.46% of JavaScript online submissions for Search Insert Position.