/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @return {number[][]}
*/
var levelOrder = function (root) {
//큐를 꺼내기 전에 그요소에 들어있는 자식들을 큐에 추가해줌
let queue = [];
let answer = [];
queue.push(root);
while (queue.length) {
let layer = [];
let len = queue.length;
for (let i = 0; i < len; i++) {
let node = queue.shift();
layer.push(node.val);
if (node.left) {
queue.push(node.left);
}
if (node.right) {
queue.push(node.right);
}
}
answer.push(layer);
}
return answer;
};
Given a string path, which is an absolute path (starting with a slash '/') to a file or directory in a Unix-style file system, convert it to the simplified canonical path.
In a Unix-style file system, a period '.' refers to the current directory, a double period '..' refers to the directory up a level, and any multiple consecutive slashes (i.e. '//') are treated as a single slash '/'. For this problem, any other format of periods such as '...' are treated as file/directory names.
The canonical path should have the following format:
Return the simplified canonical path.
Example 1:
Input: path = "/home/"
Output: "/home"
Explanation: Note that there is no trailing slash after the last directory name.
Example 2:
Input: path = "/../"
Output: "/"
Explanation: Going one level up from the root directory is a no-op, as the root level is the highest level you can go.
Example 3:
Input: path = "/home//foo/"
Output: "/home/foo"
Explanation: In the canonical path, multiple consecutive slashes are replaced by a single one.
Example 4:
Input: path = "/a/./b/../../c/"
Output: "/c"
Constraints:
1 <= path.length <= 3000
path consists of English letters, digits, period '.', slash '/' or '_'.
path is a valid absolute Unix path.
/**
* @param {string} path
* @return {string}
*/
var simplifyPath = function(path) {
let splitPath = path.split('/');
let stack = [];
for(let i = 0; i < splitPath.length; i++){
if(splitPath[i] === '.' || splitPath[i] === ''){
continue;
}
if(splitPath[i] === '..'){
stack.pop();
continue;
}
stack.push(splitPath[i]);
}
return '/' + stack.join('/');
};
풀이
var zigzagLevelOrder = function(root) {
if(!root) return [];
let queue = [];
let answer = [];
let flag = true;
queue.push(root);
while(queue.length){
let layer = [];
let len = queue.length;
for(let i = 0; i < len; i++){
let temp = queue.shift();
if(temp){
if(flag){
layer.push(temp.val);
}else{
layer.unshift(temp.val);
}
}
if(temp && temp.left){
queue.push(temp.left);
}
if(temp && temp.right){
queue.push(temp.right);
}
}
answer.push(layer);
flag = !flag
}
return answer;
};
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @return {number[]}
*/
var rightSideView = function(root) {
if(!root) return [];
let queue = [];
let answer = [];
queue.push(root);
while(queue.length){
let len = queue.length;
for(let i = 0; i < len; i++){
let temp = queue.shift();
if(temp.left){
queue.push(temp.left);
}
if(temp.right){
queue.push(temp.right);
}
if(i === len-1){
answer.push(temp.val);
}
}
}
return answer;
};
소수점 반올림등 소수점 표시할 때 :
ex)let num = 0.1666666666666 -> 소수점 6자리에서 반올림 Math.round(num * 10**6)/10**6
= 0.166667 또는 num.toFixed(6)
= "0.166667"(문자열로됨)
참조 : 아는만큼 보여요 블로그
세상에는 정말 뛰어난 사람들이 많다. 자만하지말고 주께 의지하고 꾸준히 나아가자.