Advanced Select

문제

https://www.hackerrank.com/challenges/the-pads/problem?isFullScreen=true

Generate the following two result sets:

1. Query an alphabetically ordered list of all names in OCCUPATIONS, immediately followed by the first letter of each profession as a parenthetical (i.e.: enclosed in parentheses). For example: AnActorName(A), ADoctorName(D), AProfessorName(P), and ASingerName(S).
2. Query the number of ocurrences of each occupation in OCCUPATIONS. Sort the occurrences in ascending order, and output them in the following format:
   There are a total of [occupation_count][occupation]s.

where [occupation_count] is the number of occurrences of an occupation in OCCUPATIONS and [occupation] is the lowercase occupation name. If more than one Occupation has the same [occupation_count], they should be ordered alphabetically.

Note: There will be at least two entries in the table for each type of occupation.

Input Format

The OCCUPATIONS table is described as follows: Occupation will only contain one of the following values: Doctor, Professor, Singer or Actor.

Sample Input

An OCCUPATIONS table that contains the following records:

Sample Output
Ashely(P)
Christeen(P)
Jane(A)
Jenny(D)
Julia(A)
Ketty(P)
Maria(A)
Meera(S)
Priya(S)
Samantha(D)
There are a total of 2 doctors.
There are a total of 2 singers.
There are a total of 3 actors.
There are a total of 3 professors.

<내 코드>

SELECT CONCAT(name, '(', SUBSTRING(occupation, 1, 1),')')
FROM occupations
ORDER BY name, SUBSTRING(occupation,1,1);

SELECT CONCAT('There are a total of ', COUNT(occupation), ' ',LOWER(occupation),'s.')
FROM occupations
GROUP BY occupation
ORDER BY COUNT(occupation), occupation;