문제
Given a table events with the following structure:
create table events (
event_type integer not null,
value integer not null,
time timestamp not null,
unique(event_type, time)
);
write an SQL query that, for each event_type that has been registered more than once, returns the difference between the latest (i.e. the most recent in terms of time) and the second latest value. The table should be ordered by event_type (in ascending order).
For example, given the following data:
event_type | value | time
------------+------------+--------------------
2 | 5 | 2015-05-09 12:42:00
4 | -42 | 2015-05-09 13:19:57
2 | 2 | 2015-05-09 14:48:30
2 | 7 | 2015-05-09 12:54:39
3 | 16 | 2015-05-09 13:19:57
3 | 20 | 2015-05-09 15:01:09
your query should return the following rowset:
event_type | value
------------+-----------
2 | -5
3 | 4
For the event_type 2, the latest value is 2 and the second latest value is 7, so the difference between them is −5.
The names of the columns in the rowset don't matter, but their order does.
해설
select
second_event.event_type,
first_event.value - second_event.value as value
from
(
select
*
from
(
select
*,
row_number() over (partition by event_type order by time desc) as rn
from events
) events
where rn = 2
) as second_event
join
(
select
*
from
(
select
*,
row_number() over (partition by event_type order by time desc) as rn
from events
) events
where rn = 1
) as first_event
on second_event.event_type = first_event.event_type
order by second_event.event_type