문제 링크

https://www.hackerrank.com/challenges/making-anagrams/problem

문제 풀이

from collections import Counter

def makingAnagrams(s1, s2):
    # Write your code here
    cnt1 = Counter(s1)
    cnt2 = Counter(s2)
    check = []
    answer = 0
    for c in cnt1:
        if c in cnt2:
            answer += abs(cnt1[c]-cnt2[c])
        else:
            answer += cnt1[c]
        check.append(c)
    
    for c in cnt2:
        if c not in cnt1 and c not in check:
            answer += cnt2[c]
    return answer

• Counter 변수의 덧셈, 뺄셈이 가능하다!!!
• 활용한 풀이

from collections import Counter

def makingAnagrams(s1, s2):
    # Write your code here
    cnt1 = Counter(s1)
    cnt2 = Counter(s2)
    answer = 0
    for _, v in (cnt1-cnt2).items():
        answer += v
    for _, v in (cnt2-cnt1).items():
        answer += v
    return answer