| https://www.youtube.com/watch?v=HN_95ObHAiw&t=1698s
select n
, case n
when 1 then 'one'
when 2 then 'two'
else 'many'
end as name
from (values 1,2,3,4) as t(n)
select n
, case
when n = 1 then 'a'
when n in (2,3) then 'b'
else 'c'
end as name
from (values 1,2,3,4) as t(n)
-- 에러 발생
select
8/0 as div_zero, -- DIVISION_BY_ZERO: / by zero
cast('abc' as integer) as not_int, -- INVALID_CAST_ARGUMENT: Cannot cast 'abc' to INT
2000000000 + 2000000000 as overflow -- NUMERIC_VALUE_OUT_OF_RANGE: integer addition overflow
-- 무시하고 넘어가고 싶을 경우 try 함수 사용한다.
select
try(8/0) as div_zero,
try(cast('abc' as integer)) as not_int,
try(2000000000 + 2000000000) as overflow
lambda expression with one input : x -> x + 8
lambda expression with two inputs " (x,y) -> x+y