Codility - FrogJmp / JavaScript 문제 해석 및 풀이

gimoeni·2019년 10월 18일
0

알고리즘 공부

목록 보기
4/6

A small frog wants to get to the other side of the road. The frog is currently located at position X and wants to get to a position greater than or equal to Y. The small frog always jumps a fixed distance, D.

Count the minimal number of jumps that the small frog must perform to reach its target.

Write a function:

function solution(X, Y, D);

that, given three integers X, Y and D, returns the minimal number of jumps from position X to a position equal to or greater than Y.

For example, given:

X = 10
Y = 85
D = 30
the function should return 3, because the frog will be positioned as follows:

after the first jump, at position 10 + 30 = 40
after the second jump, at position 10 + 30 + 30 = 70
after the third jump, at position 10 + 30 + 30 + 30 = 100
Write an efficient algorithm for the following assumptions:

X, Y and D are integers within the range [1..1,000,000,000];
X ≤ Y.
Copyright 2009–2019 by Codility Limited. All Rights Reserved. Unauthorized copying, publication or disclosure prohibited.

나의 풀이

function solution(X, Y, D) {
    const minDistance = Y - X;
    return minDistance % D ? (Math.floor(minDistance / D) + 1) :  (Math.floor(minDistance / D))
}
profile
2년차 프론트엔드 개발자

0개의 댓글