Write a function that reverses a string. The input string is given as an array of characters s
.
You must do this by modifying the input array in-place
with O(1)
extra money.
Input : s = ["h","e","l","l","o"]
Output : ["o","l","l","e","h"]
Input : s = ["H","a","n","n","a","h"]
Output : ["h","a","n","n","a","H"]
1 <= s.length <= 10^5
s[i]
is a printable ascii character.class Solution(object):
def reverseString(self, s):
"""
:type s: List[str]
:rtype: None Do not return anything, modify s in-place instead.
"""
s.reverse()
class Solution(object):
def reverseString(self, s):
"""
:type s: List[str]
:rtype: None Do not return anything, modify s in-place instead.
"""
left, right = 0, len(s)-1
while left < right :
s[left],s[right]=s[right],s[left]
left, right = left + 1, right - 1