SWEA 1284

반복문을 통해 수도 요금제를 계산하는 문제

T = int(input())
for test_case in range(1, T + 1):
    a = list(map(int,input().split()))
    basemoney_A = a[0]
    basemoney_B = a[1]
    below_Rwater = a[2]
    below_Rmoney = a[3]
    spent_water = a[4]


    money1 = basemoney_A*spent_water 
    if spent_water<=below_Rwater:
        money2 = basemoney_B
    else:
        money2 = basemoney_B+below_Rmoney*(spent_water-below_Rwater)

    if money1 > money2:
        print(f'#{test_case} {money2}')
    else:
        print(f'#{test_case} {money1}')