
package BOJ.step12;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;
public class BOJ2798 {
public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
StringTokenizer st = new StringTokenizer(br.readLine());
int N = Integer.parseInt(st.nextToken());
int M = Integer.parseInt(st.nextToken());
st = new StringTokenizer(br.readLine());
int[] A = new int[N];
for (int i = 0; i < N; i++) {
A[i] = Integer.parseInt(st.nextToken());
}
int Max = 0;
for (int i = 0; i < N; i++) {
for (int j = i + 1; j < N; j++) {
for (int k = j+1; k < N; k++) {
int temp = A[i] + A[j] + A[k];
if (temp <= M && temp > Max) {
Max = temp;
}
}
}
}
System.out.println(Max);
}
}
N 의 수가 크지않으므로 모든 경우의 수 찾아도 괜찮다