def solution(n):
answer=''
for i in range(0,n):
if i%2==0:
answer+='수'
else:
answer+='박'
return answer
def water_melon(n):
s = "수박" * n
return s[:n]
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def water_melon(n):
return "수박"*(n//2) + "수"*(n%2)