백준 알고리즘 12834번 : 주간 미팅

Zoo Da·2021년 10월 14일
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백준 알고리즘

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링크

https://www.acmicpc.net/problem/12834

sol1) 다익스트라

#pragma GCC optimize("O3")
#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
#include<bits/stdc++.h>
#define X first
#define Y second
#define pb push_back
#define fastio cin.tie(0)->sync_with_stdio(0)
#define MAX(a, b) (((a) > (b)) ? (a) : (b))
#define sz(v) (int)(v).size()
#define all(v) v.begin(), v.end()
#define rall(v) (v).rbegin(), (v).rend()
#define compress(v) sort(all(v)), (v).erase(unique(all(v)), (v).end())
#define OOB(x, y) ((x) < 0 || (x) >= n || (y) < 0 || (y) >= m)
#define debug(x) cout << (#x) << ": " << (x) << '\n'
using namespace std;
using ll = long long;
using ull = unsigned long long;
using dbl = double;
using ldb = long double;
using pii = pair<int,int>;
using pll = pair<ll,ll>;
using vi = vector<int>;
using vs = vector<string>;
using tii = tuple<int,int,int>;
template<typename T> using wector = vector<vector<T>>;

const int MOD = 1e9 + 7;
const int INF = 1e9 + 7;
const ll LNF = 1e18 + 7;

vector<pii> adj[1001];

int dijk(int st, int en){
  vi dist(1001, INF);
  priority_queue<pii, vector<pii>, greater<pii>> PQ;
  dist[st] = 0;
  PQ.push({0, st});

  while(!PQ.empty()){
    auto [weight, cur] = PQ.top(); PQ.pop();
    if(dist[cur] < weight) continue;
    if(cur == en) return dist[en];
    for(auto [nWeight, nxt] : adj[cur]){
      if(dist[nxt] > nWeight + weight){
        dist[nxt] = nWeight + weight;
        PQ.push({dist[nxt], nxt});
      }
    }
  }
  return -1;
}

int main() {
	fastio;
  int n,v,e; cin >> n >> v >> e; // n : 인원,v : 장소,e :도로
  int a,b; cin >> a >> b; // a : kist위치, b : 씨알 위치
  vi member(n);
  for(int i = 0; i < n; i++) cin >> member[i];
  for(int i = 0; i < e; i++){
    int u,v,w; cin >> u >> v >> w;
    adj[u].pb({w, v});
    adj[v].pb({w, u});
  }
  // Get dist
  vi ans;
  for(int i = 0; i < n; i++){
    int homeToKist = dijk(member[i], a),homeToC = dijk(member[i], b);
    int total = homeToKist + homeToC;
    ans.pb(total);
  }
  cout << accumulate(all(ans), 0) << "\n";
  return 0;
}
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