Given the root of a binary tree, determine if it is a valid binary search tree (BST).
A valid BST is defined as follows:
The left subtree of a node contains only nodes with keys less than the node's key.
The right subtree of a node contains only nodes with keys greater than the node's key.
Both the left and right subtrees must also be binary search trees.
Input: root = [2,1,3]
Output: true
Input: root = [5,1,4,null,null,3,6]
Output: false
Explanation: The root node's value is 5 but its right child's value is 4.
The number of nodes in the tree is in the range [1, }].
<= Node.val <= - 1
// https://leetcode.com/problems/validate-binary-search-tree/description/
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution
{
public:
bool isPossible(TreeNode *root, long long l, long long r)
{
if (root == nullptr)
return true;
if (root->val < r && root->val > l)
return isPossible(root->left, l, root->val) && isPossible(root->right, root->val, r);
else
return false;
}
bool isValidBST(TreeNode *root)
{
long long int min = -1000000000000;
long long int max = 1000000000000;
return isPossible(root, min, max);
}
};
false case
true case