Even or Odd : codewars javascript

front·2022년 11월 10일

kata

Create a function that takes an integer as an argument and returns "Even" for even numbers or "Odd" for odd numbers.

my answer

function evenOrOdd(number) {
  if (number%2 === 0){
    return "Even"
  } else {
    return "Odd"
  }
}

best answer

function even_or_odd(number) {
  return number % 2 ? "Odd" : "Even"
}
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