[algorithm] 프로그래머스 행렬태두리 회전

코드깎는 노인·2021년 10월 24일
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https://programmers.co.kr/learn/courses/30/lessons/77485?language=javascript

function solution(rows, columns, queries) {
    var answer = []
    let count=1
    let matrix=[]
    let row=[]
    let temp1,temp2,k,min
    for(let i=0;i<rows;i++){
        row=[]
        for(let j=0;j<columns;j++){
            row[j]=count
            count++
        }
        matrix.push(row);
    }
    for(let query of queries){
            temp1=matrix[query[0]-1][query[1]-1]
            min=temp1;
        for(k=query[1]-1;k<query[3]-1&&k<=columns-1;k++){
            temp2=matrix[query[0]-1][k+1]
            matrix[query[0]-1][k+1]=temp1
            temp1=temp2
            if(min>temp1){
               min=temp1;
            }
        }
        for(k=query[0];k<query[2]&&k<=rows-1;k++){
            temp2=matrix[k][query[3]-1]
            matrix[k][query[3]-1]=temp1
            temp1=temp2
            if(min>temp1){
               min=temp1;
            }
        }
        for(k=query[3]-2;k>query[1]-2&&k>=0;k--){
            temp2=matrix[query[2]-1][k]
            matrix[query[2]-1][k]=temp1
            temp1=temp2
            if(min>temp1){
               min=temp1;
            }
        }
        for(k=query[2]-2;k>query[0]-2&&k>=0;k--){
            temp2=matrix[k][query[1]-1]
            matrix[k][query[1]-1]=temp1
            temp1=temp2
            if(min>temp1){
               min=temp1;
            }
        }
        answer.push(min)
    }    
    
    return answer;
}
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