1321. Restaurant Growth

• 문제
  
• 정답

SELECT
    visited_on,
    (
        SELECT SUM(amount)
        FROM customer
        WHERE visited_on BETWEEN DATE_SUB(c.visited_on, INTERVAL 6 DAY) AND c.visited_on
    ) AS amount,
    ROUND(
        (
            SELECT SUM(amount) / 7
            FROM customer
            WHERE visited_on BETWEEN DATE_SUB(c.visited_on, INTERVAL 6 DAY) AND c.visited_on
        ),
        2
    ) AS average_amount
FROM customer c
WHERE visited_on >= (
        SELECT DATE_ADD(MIN(visited_on), INTERVAL 6 DAY)
        FROM customer
    )
GROUP BY visited_on;

• 결과