Java Exception Handling (Try-catch)

• 문제
  
• 정답

import java.io.*;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        try {
            int x = scanner.nextInt();
            int y = scanner.nextInt();
            System.out.println(x / y);
        } catch (InputMismatchException e) {
            System.out.println("java.util.InputMismatchException");
        } catch (ArithmeticException e) {
            System.out.println("java.lang.ArithmeticException: " + e.getMessage());
        }
    }
}

• 결과