The PADS

윤지현·2024년 10월 22일

SQL(Programmers)

목록 보기
149/184
  • 문제
  • 정답
SELECT CONCAT(name, '(', substring(occupation, 1, 1), ')')
FROM Occupations
ORDER BY name, substring(occupation, 1, 1);

SELECT CONCAT('There are a total of ', count(occupation), ' ', LOWER(occupation), 's.')
FROM Occupations
GROUP BY occupation
ORDER BY count(occupation), occupation
  • 결과
profile
첫 시작

0개의 댓글