즐겨찾기가 가장 많은 식당 정보 출력하기

SELECT FOOD_TYPE, REST_ID, REST_NAME, FAVORITES
FROM REST_INFO
WHERE (FOOD_TYPE,FAVORITES) 
IN 
(
    SELECT FOOD_TYPE, MAX(FAVORITES) 
    FROM REST_INFO
    GROUP BY FOOD_TYPE
)
ORDER BY FOOD_TYPE DESC;