https://school.programmers.co.kr/learn/courses/30/lessons/42840
import numpy as np
def solution(answers):
answer = []
s1 = [1, 2, 3, 4, 5]
s2 = [2, 1, 2, 3, 2, 4, 2, 5]
s3 = [3, 3, 1, 1, 2, 2, 4, 4, 5, 5]
for s in [s1, s2, s3]:
answer.append([a==s[i%len(s)] for i, a in enumerate(answers)].count(True))
if answer.count(max(answer)) > 0:
return (np.where(np.array(answer)==max(answer))[0]+1).tolist()
#numpy #where