


from collections import deque #bfs
n = int(input())
max_num = 0
graph = []
for _ in range(n):
low = list(map(int, input().split()))
graph.append(low)
for i in low:
if i > max_num:
max_num = i # 최대값 , 제일 높은 지대
dx = [0, 0, -1, 1]
dy = [1, -1, 0, 0]
def bfs(x, y, num):
queue = deque()
queue.append((x, y))
visited[x][y] = 1
while queue:
x, y = queue.popleft()
for i in range(4):
nx = dx[i] + x
ny = dy[i] + y
if 0 <= nx < n and 0 <= ny < n:
if graph[nx][ny] > num and visited[nx][ny] == 0:
visited[nx][ny] = 1 # 안전지대라면 1로 방문처리
queue.append((nx, ny))
result = []
for i in range(max_num):
cnt = 0
visited = [[0]*n for _ in range(n)]
for j in range(n):
for k in range(n):
if graph[j][k] > i and visited[j][k] == 0:
bfs(j, k, i)
cnt += 1
result.append(cnt)
print(max(result))