KOISTUDY - 공주를 구해라.
BFS로 풀어보았습니다!
import java.io.*;
import java.util.*;
//공주를 구해라.
public class 공주를구해라 {
static ArrayList<Integer>[] graph;
static int N, M;
static int S, E;
public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
StringTokenizer st = new StringTokenizer(br.readLine());
N = Integer.parseInt(st.nextToken());
M = Integer.parseInt(st.nextToken());
graph = new ArrayList[N + 1];
for (int i = 1; i <= N; i++) {
graph[i] = new ArrayList<>();
}
for (int i = 0; i < M; i++) {
st = new StringTokenizer(br.readLine());
int a = Integer.parseInt(st.nextToken());
int b = Integer.parseInt(st.nextToken());
graph[a].add(b);
graph[b].add(a);
}
st = new StringTokenizer(br.readLine());
S = Integer.parseInt(st.nextToken());
E = Integer.parseInt(st.nextToken());
System.out.println(bfs(S, E));
}
static int bfs(int start, int end) {
boolean[] visited = new boolean[N + 1];
Queue<int[]> q = new ArrayDeque<>();
q.add(new int[]{start, 0});
visited[start] = true;
while (!q.isEmpty()) {
int[] cur = q.poll();
int node = cur[0];
int dist = cur[1];
if (node == end) return dist;
for (int next : graph[node]) {
if (!visited[next]) {
visited[next] = true;
q.add(new int[]{next, dist + 1});
}
}
}
return 0;
}
}