def find_name(a):
name_dict={}
for name in a:
if name in name_dict:
name_dict[name]+=1
else:
name_dict[name]=1
result=set()
for name in name_dict:
if name_dict[name]>=2:
result.add(name)
return result
name=['tom','jerry','mike','tom']
print(find_name(name))
name2=['tom','jerry','mike','tom','mike']
print(find_name(name2))
코드를 입력하세요
문제12-1
a=int(input())
def return_name(name):
for n in name:
if a in name:
return name[n]
else:
return '?' #print 대신 return 써야 none값이 안나온다.
name_1={
39:'justine',
14:'john',
67:'mike',
105:'summer'
}
#print(name_1[0])
print(return_name(name_1))