https://www.hackerrank.com/challenges/the-company
SELECT c.company_code
, c.founder
, COUNT(DISTINCT lm.lead_manager_code)
, COUNT(DISTINCT sm.senior_manager_code)
, COUNT(DISTINCT m.manager_code)
, COUNT(DISTINCT e.employee_code)
FROM Company c
LEFT JOIN Lead_Manager lm ON c.company_code = lm.company_code
LEFT JOIN Senior_Manager sm ON c.company_code = sm.company_code
LEFT JOIN Manager m ON c.company_code = m.company_code
LEFT JOIN Employee e ON c.company_code =e.company_code
GROUP BY c.company_code, c.founder
ORDER BY c.company_code