튜플안의 숫자의 나열을 참고하여, 원래 숫자 배열을 산출
https://programmers.co.kr/learn/courses/30/lessons/64065

22-04-27 code

def solution(s):
    s = s.replace("{","[")
    s = s.replace("}","]")

    answer = []
    pre_set = set([])
    for e_s in sorted(eval(s),key= lambda x : len(x)):
        answer.append(list(set(e_s) - pre_set)[0])
        pre_set = set(e_s)
    return answer

Tips.
1. 정규 표현식 사용 (참고: https://velog.io/@geonhwi/%EC%A0%95%EA%B7%9C%ED%91%9C%ED%98%84%EC%8B%9D-2)
2. import re
3. from collection import Counter

22-05-10

import re
from collections import Counter

def solution(s):

    numbers = Counter(re.findall(r'\d+',s))
    ans = sorted(numbers,key = lambda x : numbers[x], reverse = True)
    return list(map(int,ans))

1. map을 이용하여 list 내의 str을 int로 변환