Given two integer arrays startTime and endTime and given an integer queryTime.
The ith student started doing their homework at the time startTime[i] and finished it at time endTime[i].
Return the number of students doing their homework at time queryTime. More formally, return the number of students where queryTime lays in the interval [startTime[i], endTime[i]] inclusive.
- 두 개의 정수 배열 startTime 및 endTime과 정수 queryTime이 제공
- i 번째 학생은 startTime[i] 에 숙제를 시작하여 endTime[i] 에 숙제를 마침
- queryTime 시간에 숙제를하는 학생 수를 반환(공식적으로, queryTime이 [startTime [i], endTime [i]] 간격으로 놓인 학생 수를 반환)
exmaple
Example 1:
Input: startTime = [1,2,3], endTime = [3,2,7], queryTime = 4
Output: 1
Explanation: We have 3 students where:
The first student started doing homework at time 1 and finished at time 3 and wasn't doing anything at time 4.
The second student started doing homework at time 2 and finished at time 2 and also wasn't doing anything at time 4.
The third student started doing homework at time 3 and finished at time 7 and was the only student doing homework at time 4.Example 2:
Input: startTime = [4], endTime = [4], queryTime = 4
Output: 1
Explanation: The only student was doing their homework at the queryTime.Example 3:
Input: startTime = [4], endTime = [4], queryTime = 5
Output: 0Example 4:
Input: startTime = [1,1,1,1], endTime = [1,3,2,4], queryTime = 7
Output: 0Example 5:
Input: startTime = [9,8,7,6,5,4,3,2,1], endTime = [10,10,10,10,10,10,10,10,10], queryTime = 5
Output: 5
/**
* @param {number[]} startTime
* @param {number[]} endTime
* @param {number} queryTime
* @return {number}
*/
var busyStudent = function(startTime, endTime, queryTime) {
const timeLength = startTime.length;
let busyStudentCount = 0;
for(let i = 0; i < timeLength; i++) {
if(startTime[i] <= queryTime && endTime[i] >= queryTime) {
busyStudentCount++;
}
}
return busyStudentCount;
};