Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward as forward.
Follow up: Could you solve it without converting the integer to a string?
Example 1:
Input: x = 121
Output: true
Example 2:
Input: x = -121
Output: false
Explanation: From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.
Example 3:
Input: x = 10
Output: false
Explanation: Reads 01 from right to left. Therefore it is not a palindrome.
Example 4:
Input: x = -101
Output: false
Constraints:
class Solution:
def isPalindrome(self, x: int) -> bool:
ret=None
if x < 0:
ret=False
else:
original=x
reverse=0
while x:
remainder=x%10
x=x//10
reverse=reverse*10+remainder
if reverse == original:
ret=True
else:
ret=False
return ret
Time complexity :
x=12 , reverse=0
quotient | remainder | reverse |
---|---|---|
1 | 2 | 0*10+2=2 |
0 | 1 | 2*10+1=21 |