튜플을 set 형태의 튜플로 만들어야 한다.
def solution(s):
answer = []
# 정규 표현식을 이용해서 {,}을 없애준다
s = s.lstrip('{').rstrip('}').split('},{')
# s = s.replace("{","").replace("}","").split(",")
# print(s)
temp = []
for i in s:
temp.append(list(map(int, i.split(','))))
temp.sort(key = lambda x: len(x))
for t in temp:
for i in t:
if i not in answer:
answer.append(i)
return answer
정규표현식 + Counter
re.findall('\d+', s)
Counter({'2': 4, '1': 3, '3': 2, '4': 1})
import re
from collections import Counter
def solution(s):
answer = []
s = Counter(re.findall('\d+', s))
# print(s)
# Counter({'2': 4, '1': 3, '3': 2, '4': 1})
for k, v in sorted(s.items(), key=lambda x: x[1], reverse=True):
answer.append(int(k))
return answer