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์ฝ”๋“ฑ์–ดยท2024๋…„ 11์›” 19์ผ
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๋ชฉ๋ก ๋ณด๊ธฐ
1/19

sparta_employees(์ง์›) ํ…Œ์ด๋ธ”

idnamepositionsalaryhire_date
1๋ฅดํƒ„์ด๊ฐœ๋ฐœ์ž300002022-05-01
2๋ฐฐ์บ ์ดPM400002021-09-25
3๊ตฌ๊ตฌ์ดํŒŒํŠธ์žฅ350002023-06-01
4์ด์„ ์ดํŒ€์žฅ500002021-07-09

ํ…Œ์ด๋ธ” ์ž‘์„ฑ, ๋ฐ์ดํ„ฐ ์‚ฝ์ž… ์ฟผ๋ฆฌ

create table sparta_employees
(
	id int,
	name varchar(10),
	position varchar(10),
	salary int,
	hire_date date
);

insert into sparta_employees(id, name, position, salary, hire_date) values
(1, "๋ฅดํƒ„์ด", "๊ฐœ๋ฐœ์ž", 30000, "2022-05-01"),
(2, "๋ฐฐ์บ ์ด", "PM", 40000, "2021-09-25"),
(3, "๊ตฌ๊ตฌ์ด", "ํŒŒํŠธ์žฅ", 35000, "2023-06-01"),
(4, "์ด์…˜์ด", "ํŒ€์žฅ", 50000, "2021-07-09");

์—ฐ์Šต ๋ฌธ์ œ

  1. sparta_employeesํ…Œ์ด๋ธ”์—์„œ ๋ชจ๋“  ์ง์›์˜ ์ด๋ฆ„(name)๊ณผ ์ง๊ธ‰(position)์„ ์„ ํƒํ•˜๋Š” ์ฟผ๋ฆฌ๋ฅผ ์ž‘์„ฑํ•ด์ฃผ์„ธ์š”.
select name, position
from sparta_employees;
  1. sparta_employeesํ…Œ์ด๋ธ”์—์„œ ์ค‘๋ณต ์—†์ด ๋ชจ๋“  ์ง๊ธ‰(position)์„ ์„ ํƒํ•˜๋Š” ์ฟผ๋ฆฌ๋ฅผ ์ž‘์„ฑํ•ด์ฃผ์„ธ์š”.
select distinct position
from sparta_employees;
  1. sparta_employeesํ…Œ์ด๋ธ”์—์„œ ์—ฐ๋ด‰(salary)์ด 40000๊ณผ 60000 ์‚ฌ์ด์ธ ์ง์›๋“ค์„ ์„ ํƒํ•˜๋Š” ์ฟผ๋ฆฌ๋ฅผ ์ž‘์„ฑํ•ด์ฃผ์„ธ์š”.
select * 
from sparta_employees
where salary between 40000 and 60000;
  1. sparta_employeesํ…Œ์ด๋ธ”์—์„œ ์ž…์‚ฌ์ผ(hire_date)์ด 2023๋…„ 1์›” 1์ผ ์ด์ „์ธ ๋ชจ๋“  ์ง์›๋“ค์„ ์„ ํƒํ•˜๋Š” ์ฟผ๋ฆฌ๋ฅผ ์ž‘์„ฑํ•ด์ฃผ์„ธ์š”.
select * 
from sparta_employees
where hire_date < "2023-01-01";
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