[LeetCode] Backspace String Compare - JavaScript

👩🏻‍💻 문제

LeetCode #844 Backspace String Compare

👩🏻‍💻 풀이

var backspaceCompare = function(s, t) {
    s = s.split("");
    t = t.split("");
    
    function removeBackspace(arr) {
        let index = arr.indexOf("#");
        if(arr[index-1]) { 
            arr.splice(index-1, 2);
        } else {
            arr.splice(index, 1);
        }
        return arr.includes("#") ? removeBackspace(arr) : arr;
    }
    if(s.includes("#")) removeBackspace(s);
    if(t.includes("#")) removeBackspace(t);
    
    return s.join("") === t.join("");
};

// 다른 분의 풀이
/**
 * @param {string} s
 * @return {string}
 */
const process = s => {
    const res = [];
    for (x of s.split('')) {
        x === '#' ? res.pop() : res.push(x);
    }
    return res.join('')
}
/**
 * @param {string} S
 * @param {string} T
 * @return {boolean}
 */
var backspaceCompare = (S, T) => process(S) == process(T);