문제 링크
https://leetcode.com/problems/students-and-examinations/description/
Table: Students
+---------------+---------+
| Column Name | Type |
+---------------+---------+
| student_id | int |
| student_name | varchar |
+---------------+---------+
student_id is the primary key (column with unique values) for this table.
Each row of this table contains the ID and the name of one student in the school.
Table: Subjects
+--------------+---------+
| Column Name | Type |
+--------------+---------+
| subject_name | varchar |
+--------------+---------+
subject_name is the primary key (column with unique values) for this table.
Each row of this table contains the name of one subject in the school.
Table: Examinations
+--------------+---------+
| Column Name | Type |
+--------------+---------+
| student_id | int |
| subject_name | varchar |
+--------------+---------+
There is no primary key (column with unique values) for this table. It may contain duplicates.
Each student from the Students table takes every course from the Subjects table.
Each row of this table indicates that a student with ID student_id attended the exam of subject_name.
Write a solution to find the number of times each student attended each exam.
Return the result table ordered by student_id and subject_name.
The result format is in the following example.
Example 1:
Input:
Students table:
+------------+--------------+
| student_id | student_name |
+------------+--------------+
| 1 | Alice |
| 2 | Bob |
| 13 | John |
| 6 | Alex |
+------------+--------------+
Subjects table:
+--------------+
| subject_name |
+--------------+
| Math |
| Physics |
| Programming |
+--------------+
Examinations table:
+------------+--------------+
| student_id | subject_name |
+------------+--------------+
| 1 | Math |
| 1 | Physics |
| 1 | Programming |
| 2 | Programming |
| 1 | Physics |
| 1 | Math |
| 13 | Math |
| 13 | Programming |
| 13 | Physics |
| 2 | Math |
| 1 | Math |
+------------+--------------+
Output:
+------------+--------------+--------------+----------------+
| student_id | student_name | subject_name | attended_exams |
+------------+--------------+--------------+----------------+
| 1 | Alice | Math | 3 |
| 1 | Alice | Physics | 2 |
| 1 | Alice | Programming | 1 |
| 2 | Bob | Math | 1 |
| 2 | Bob | Physics | 0 |
| 2 | Bob | Programming | 1 |
| 6 | Alex | Math | 0 |
| 6 | Alex | Physics | 0 |
| 6 | Alex | Programming | 0 |
| 13 | John | Math | 1 |
| 13 | John | Physics | 1 |
| 13 | John | Programming | 1 |
+------------+--------------+--------------+----------------+
Explanation:
The result table should contain all students and all subjects.
Alice attended the Math exam 3 times, the Physics exam 2 times, and the Programming exam 1 time.
Bob attended the Math exam 1 time, the Programming exam 1 time, and did not attend the Physics exam.
Alex did not attend any exams.
John attended the Math exam 1 time, the Physics exam 1 time, and the Programming exam 1 time.도출 과정
SELECT e.student_id, e.subject_name, COUNT(e.subject_name) as count
FROM Students st RIGHT JOIN Examinations e
ON st.student_id = e.student_id
GROUP BY e.student_id, e.subject_name실행결과
| student_id | subject_name | count |
| ---------- | ------------ | ----- |
| 1 | Math | 3 |
| 1 | Physics | 2 |
| 1 | Programming | 1 |
| 2 | Programming | 1 |
| 13 | Math | 1 |
| 13 | Programming | 1 |
| 13 | Physics | 1 |
| 2 | Math | 1 |
해당 컬럼들을 아이디별 SUBJECT 들 사이에 끼워넣고 싶었는데
막혔다.
나의 정답
SELECT sub1.student_id, sub1.student_name, sub1.subject_name, IFNULL(sub2.count,0) as attended_exams FROM (SELECT * FROM Students st CROSS JOIN Subjects sb ) sub1 LEFT JOIN (SELECT e.student_id, e.subject_name, COUNT(e.subject_name) as count FROM Students st RIGHT JOIN Examinations e ON st.student_id = e.student_id GROUP BY e.student_id, e.subject_name ) sub2 on sub1.student_id = sub2.student_id and sub1.subject_name= sub2.subject_name ORDER BY sub1.student_id, sub1.subject_name
