[SQL_Q] 1084. Sales Analysis III

문제 링크 : https://leetcode.com/problems/sales-analysis-iii/description/

Table: Product

+--------------+---------+
| Column Name  | Type    |
+--------------+---------+
| product_id   | int     |
| product_name | varchar |
| unit_price   | int     |
+--------------+---------+
product_id is the primary key (column with unique values) of this table.
Each row of this table indicates the name and the price of each product.
Table: Sales

+-------------+---------+
| Column Name | Type    |
+-------------+---------+
| seller_id   | int     |
| product_id  | int     |
| buyer_id    | int     |
| sale_date   | date    |
| quantity    | int     |
| price       | int     |
+-------------+---------+
This table can have duplicate rows.
product_id is a foreign key (reference column) to the Product table.
Each row of this table contains some information about one sale.

문제 : Write a solution to report the products that were only sold in the first quarter of 2019. That is, between 2019-01-01 and 2019-03-31 inclusive.
Return the result table in any order.
The result format is in the following example.

Example 1:

Input: 
Product table:
+------------+--------------+------------+
| product_id | product_name | unit_price |
+------------+--------------+------------+
| 1          | S8           | 1000       |
| 2          | G4           | 800        |
| 3          | iPhone       | 1400       |
+------------+--------------+------------+
Sales table:
+-----------+------------+----------+------------+----------+-------+
| seller_id | product_id | buyer_id | sale_date  | quantity | price |
+-----------+------------+----------+------------+----------+-------+
| 1         | 1          | 1        | 2019-01-21 | 2        | 2000  |
| 1         | 2          | 2        | 2019-02-17 | 1        | 800   |
| 2         | 2          | 3        | 2019-06-02 | 1        | 800   |
| 3         | 3          | 4        | 2019-05-13 | 2        | 2800  |
+-----------+------------+----------+------------+----------+-------+
Output: 
+-------------+--------------+
| product_id  | product_name |
+-------------+--------------+
| 1           | S8           |
+-------------+--------------+
Explanation: 
The product with id 1 was only sold in the spring of 2019.
The product with id 2 was sold in the spring of 2019 but was also sold after the spring of 2019.
The product with id 3 was sold after spring 2019.
We return only product 1 as it is the product that was only sold in the spring of 2019.

내 풀이

with f_q as (
    SELECT product_id
    FROM Sales
    WHERE sale_date between  "2019-01-01" and "2019-03-31" 
), out_q as(
    SELECT product_id
    FROM Sales
    WHERE sale_date < "2019-01-01" or sale_date > "2019-03-31" 
), filtered_q as (
    SELECT product_id
    FROM f_q
    where product_id not in (SELECT * FROM out_q)
)
SELECT product_id, product_name
FROM Product
where product_id  in (SELECT * FROM filtered_q)

with dates as (
SELECT product_id, MAX(sale_date) as max_date, MIN(sale_date) as min_date
FROM Sales
GROUP BY product_id
HAVING max_date <= "2019-03-31" and min_date >= "2019-01-01"
)
SELECT distinct d.product_id, p.product_name
FROM dates d JOIN Product p
on d.product_id = p.product_id

다른 풀이

SELECT DISTINCT p.product_id, p.product_name
FROM Sales s
LEFT JOIN Product p ON p.product_id = s.product_id
GROUP BY p.product_id
HAVING MIN(sale_date) >= '2019-01-01' AND MAX(sale_date) <= '2019-03-31';

간결하게 풀리는 문제였다.