Coding 3min : Jumping Dutch act

8kyu

Description

Coding 3min : Jumping Dutch act

This is the simple version of Shortest Code series. If you need some challenges, please try the challenge version

Task:
Mr. despair wants to jump off Dutch act, So he came to the top of a building.

Scientific research shows that a man jumped from the top of the roof, when the floor more than 6, the person will often die in an instant; When the floor is less than or equal to 6, the person will not immediately die, he would scream. (without proof)

Input: floor, The height of the building (floor)

Output: a string, The voice of despair(When jumping Dutch act)

Example:
sc(2) should return "Aa~ Pa! Aa!"

It means:

Mr. despair jumped from the 2 floor, the voice is "Aa~"
He fell on the ground, the voice is "Pa!"
He did not die immediately, and the final voice was "Aa!"
sc(6) should return "Aa~ Aa~ Aa~ Aa~ Aa~ Pa! Aa!"

sc(7) should return "Aa~ Aa~ Aa~ Aa~ Aa~ Aa~ Pa!"

sc(10) should return "Aa~ Aa~ Aa~ Aa~ Aa~ Aa~ Aa~ Aa~ Aa~ Pa!"

if floor<=1, Mr. despair is safe, return ""

The final advice
Just play in this kata, Don't experiment in real life ;-)

My Solution

function sc(floor){ 
  
  let arr = [];
  
  if( 1 < floor){
    
    for(let i = 1 ; i <= floor ; i ++ ){
      i !== floor ? arr.push("Aa~") : arr.push("Pa!");
    }
  
    if(floor <= 6){
      arr.push("Aa!");
    } 
    
    return arr.join(" ");
  
  }else{
    return "";
  }

}

other Solution

function sc(floor){
  if(floor <= 1) return "";
  
  return 'Aa~ '.repeat(floor-1) + 'Pa!' + (floor<=6 ? ' Aa!': '');
}

review

배열을 push()로 각각 넣는방법도 있지만, repeat()로 문자열을 합해주는 메서드를 사용하면
간단하게 문자열을 붙일 수 있다.