Q. Implement the function unique_in_order which takes as argument a sequence and returns a list of items without any elements with the same value next to each other and preserving the original order of elements.
For example:
uniqueInOrder('AAAABBBCCDAABBB') == ['A', 'B', 'C', 'D', 'A', 'B']
uniqueInOrder('ABBCcAD') == ['A', 'B', 'C', 'c', 'A', 'D']
uniqueInOrder([1,2,2,3,3]) == [1,2,3]
//#my solution
function uniqueInOrder(it) {
let result = [];
let last;
for (let i = 0; i < it.length; i++) {
if (it[i] !== last) {
result.push((last = it[i]));
}
}
return result;
}
//#other solution
var uniqueInOrder=function(iterable){
return [...iterable].filter((a, i) => a !== iterable[i-1])
}