Find the odd int

❓ Find the odd int

Q. Given an array of integers, find the one that appears an odd number of times.

There will always be only one integer that appears an odd number of times.

Examples
[7] should return 7, because it occurs 1 time (which is odd).
[0] should return 0, because it occurs 1 time (which is odd).
[1,1,2] should return 2, because it occurs 1 time (which is odd).
[0,1,0,1,0] should return 0, because it occurs 3 times (which is odd).
[1,2,2,3,3,3,4,3,3,3,2,2,1] should return 4, because it appears 1 time (which is odd).

✔ Solution

//#my solution
const findOdd = (arr) => arr.reduce((a, b) => a ^ b);


//other solution
function findOdd(arr) {
  return arr.find((item, index) => arr.filter(el => el == item).length % 2)
}