DP 푸는법 1. 패턴 찾아보기
#include <iostream>
#include <vector>
#define MOD 1000000009
using namespace std;
void make_DP(vector<long long>& DP) {
int i, j;
DP[0] = 1;
DP[1] = 1;
DP[2] = 2;
for (i = 3; i < DP.size(); i++) {
DP[i] = (DP[i - 3] + DP[i - 2] + DP[i - 1]) % MOD;
}
return;
}
int find_answer(int n, vector<long long> &DP) {
int answer = 0;
int i, j;
answer = DP[n];
return answer;
}
int main(void) {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
int T, i, n;
vector<long long> DP(1000001, 0);
make_DP(DP);
cin >> T;
for (i = 0; i < T; i++) {
cin >> n;
cout << find_answer(n, DP) << "\n";
}
return 0;
}