어려운 문제를 결국 못풀고 쉬운 문제를 풀어버렸다.
#include <iostream>
#include <vector>
#include <queue>
using namespace std;
void input_map(vector <vector<char>> &grass, int *R, int *C)
{
int i, j;
cin >> *R >> *C;
grass.resize(*R, vector<char>(*C, ' '));
for (i = 0; i < *R; i++)
{
for (j = 0; j < *C; j++)
{
cin >> grass[i][j];
}
}
return;
}
void BFS(vector <vector<char>>& grass, vector<vector<bool>> &visited, int start_y, int start_x, int R, int C)
{
int current_x, current_y, next_x, next_y;
vector<pair<int, int>>direction{ {1, 0},{0, 1},{-1, 0},{0, -1} };
queue <pair<int, int>> q;
int i, d_size = direction.size();
visited[start_y][start_x] = true;
q.push({start_x, start_y});
while (!q.empty())
{
current_x = q.front().first;
current_y = q.front().second;
q.pop();
for (i = 0; i < d_size; i++)
{
next_x = current_x + direction[i].first;
next_y = current_y + direction[i].second;
if ((next_x >= 0 && next_x < C) && (next_y >= 0 && next_y < R)
&& (visited[next_y][next_x] == false)
&& (grass[next_y][next_x] == '#'))
{
q.push({ next_x, next_y });
visited[next_y][next_x] = true;
}
}
}
return;
}
void find_answer(vector <vector<char>>& grass, int R, int C)
{
int i, j, count = 0;
vector<vector<bool>> visited(R, vector<bool>(C, false));
for (i = 0; i < R; i++)
{
for (j = 0; j < C; j++)
{
if (grass[i][j] == '#' && visited[i][j] == false)
{
count++;
BFS(grass, visited, i, j, R, C);
}
}
}
cout << count << "\n";
return;
}
int main(void)
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
vector <vector<char>> grass;
int R, C;
input_map(grass, &R, &C);
find_answer(grass, R, C);
return 0;
}