Given the array nums
consisting of 2n
elements in the form [x1,x2,...,xn,y1,y2,...,yn]
.
Return the array in the form [x1,y1,x2,y2,...,xn,yn]
.
Example 1:
Input: nums = [2,5,1,3,4,7], n = 3
Output: [2,3,5,4,1,7]
Explanation: Since x1=2, x2=5, x3=1, y1=3, y2=4, y3=7 then the answer is [2,3,5,4,1,7].
Example 2:
Input: nums = [1,2,3,4,4,3,2,1], n = 4
Output: [1,4,2,3,3,2,4,1]
Example 3:
Input: nums = [1,1,2,2], n = 2
Output: [1,2,1,2]
Constraints:
class Solution:
def shuffle(self, nums: List[int], n: int) -> List[int]:
answer = []
for i in range(n):
answer.extend([nums[i], nums[i+n]])
return answer
O(n)
O(n)
이 문제는 공간 복잡도 O(1)
를 만족하는 로직으로도 접근해볼 수 있다. 해보세요